a = [1]
b = [2]
c = [3]
d = []
如何合并成 d = [[1], [2], [3]]?
b = [2]
c = [3]
d = []
如何合并成 d = [[1], [2], [3]]?
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This topic created in 3271 days ago, the information mentioned may be changed or developed.
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1
d.append(a)
d.append(b) d.append(c) |
1 |
2
d = [l for l in [a, b, c, d] if len(l) > 0]
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3
没看懂，d = [a, b, c] 不行吗
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5
d = [a, b, c]
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6
过滤掉 d 为[]，然后合并成个列表？
list(filter(None,[a,b,c,d])) |
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9
来个题外的，如果是要把 a、b、c 合并成[1, 2, 3]，那么可以用 d=sum([a, b, c], [])
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12
@zhengjian 嗯，我举措例子了。。。。。。。应该是展开的例子。。。。。。
>>> d = [[1,2,3], [4,5], [6,7]] >>> sum(d, []) [1, 2, 3, 4, 5, 6, 7] |
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13
@NoAnyLove 为什么不直接 a + b + c
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14
[a,b,c]直接引用应该是最快的吧
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15
@SingeeKing 因为我举错例子了。。。。。应该#12 楼的那种情况才这样用
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16
from itertools import chain
d = list(chain(a, b, c)) |
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