这样的字符串：20170618030000 如何转成这种：2017/06/18/03:00:00 或其他的 DateTime 格式
http://ww2.sinaimg.cn/large/005IRbZEgy1fuo3twiownj307a00q0si.jpg
This topic created in 2990 days ago, the information mentioned may be changed or developed.
 |
1
用 DateTime.ParseExact("20170618030000", "yyyyMMddhhmmss", CultureInfo.InvarientCulture)
PS C:\Users\hjc> [datetime]::ParseExact("20170618030000", "yyyyMMddhhmmss", [System.Globalization.CultureInfo]::InvarientCulture) Sunday, June 18, 2017 3:00:00 AM |
1
 |
geelawAug 27, 2018 via iPhone
3
@BadCat 以后先找 docs.microsoft.com
|
 |
LuffyGuOct 16, 2018
4
头像不错
|
Select Language