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11 replies • 2022-03-07 20:54:52 +08:00
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noe132Mar 7, 2022
1
你这已经是最简洁的写法了
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2
@noe132 可是继续加 SearchType 不就很难受了
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anjianshiMar 7, 2022
3
确实是最简洁的写法了...
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anjianshiMar 7, 2022
4
如果新加的 type 不需要 xSearchItems ，可以这样合并：
```typescript type Column = { xSearchType: 'input' | 'other' | 'other-other' } | { xSearchType: 'select', xSearchItems: any[] } ``` |
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zhy0216Mar 7, 2022
5
应该可以用 conditional type
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voidcommaMar 7, 2022
6
```typescript
type column<T> = T extends 'select' ? { xSearchType: T, xSearchItems: any[] } : { xSearchType: T } let c: column<'select'> = { xSearchType: 'select', xSearchItems: [], } let n: column<'input'> = { xSearchType: 'input', } ``` 暂时想到这样写，不过感觉还有更简洁的方法。 |
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zhihaofansMar 7, 2022 via iPhone
7
没学过 ts 的好奇问一下，参数名前面都带个 x 是有什么用途
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8
@zhy0216 看了下文档，没想出来怎么实现
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9
@zhihaofans 我随手写的..，跟 ts 没关系
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10
@xiaojie668329 要传泛型感觉也有点难受
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zhy0216Mar 7, 2022
11
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